-16x^2+96x+112=200

Solution for -16x^2+96x+112=200 equation:

-16x^2+96x+112=200

We move all terms to the left:

-16x^2+96x+112-(200)=0

We add all the numbers together, and all the variables

-16x^2+96x-88=0

a = -16; b = 96; c = -88;
Δ = b2-4ac
Δ = 962-4·(-16)·(-88)
Δ = 3584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3584}=\sqrt{256*14}=\sqrt{256}*\sqrt{14}=16\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-16\sqrt{14}}{2*-16}=\frac{-96-16\sqrt{14}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+16\sqrt{14}}{2*-16}=\frac{-96+16\sqrt{14}}{-32}
$